Question

Contains the origin and is parallel to the line 8x − 3y = 3

Answer 1

y=(8/3)x

Explanation:

First, we make 8x-3y=3 into the form y=mx+b

3y=8x-3

y=(8/3)x-1

For an equation to be parallel to this equation, the slope must be the same, so the new equation will be:

y=(8/3)x+b

We know that (0,0) is a point in this line. We plug (0,0) into the equation to find b:

0=(8/3)*0+b

b=0

y=(8/3)x