Pls tell me the correct option

Question

asked Apr 22, 2022 153k views

2 Answers

Jeremy Warne · Answer 1 · 2022-04-28T17:36:20+0000

Answer:

b.
(1)/(16)

Explanation:

A = {2, 3}

B = {4, 6}

C = set of all possible fractions where, the numerators are in set A and the denominators are found in Set B

The 4 possible fractions we can get for set C are as follows:

Set C: {
(2)/(4) ,
(2)/(6) ,
(3)/(4) ,
(3)/(6) }

Multiply all to get the product of all elements in Set C:

(2)/(4)*(2)/(6)*(3)/(4)*(3)/(6)

Simplify where necessary

(1)/(2)*(1)/(3)*(3)/(4)*(1)/(2)

(1*1*3*1)/(2*3*4*2)

(3)/(48)

Simply further

(1)/(16)