{( (5)/(3) )}^(2n + 1) {( (5)/(3) )}^(5) = ({ (5)/(3) )}^(n + 2) Pls include steps... ​

Question

`{( (5)/(3) )}^(2n + 1) {( (5)/(3) )}^(5) = ({ (5)/(3) )}^(n + 2)`

Pls include steps...
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Answer 1

n = -4

Explanation:

`((5)/(3) )^2^n^+^1 * ((5)/(3) )^5 = ((5)/(3))^n^+^2`

in multiplication if the base are same u can add there exponent.

`((5)/(3))^2^n^+^1^+^5 = ((5)/(3))^n^+^2`

base of both sides are equal so their exponent will be equal

2n + 1 + 5 = n + 2

2n + 6 = n + 2

2n - n = 2 - 6

n = -4