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Find'x' 2log_5x = 1+log_5(x-6/5)​

User Marc Grue
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1 Answer

2 votes

Answer:

x = 2 and x = 3

Explanation:

Formulas used :


log_5 \ 5 = 1


log_5 \ x + log_5 \ y = log_5 \ (xy)


log_5 \ x = log_5 \ y => x = y

Steps :


2 \ log_5 \ x = 1 + log_5 (x - (6)/(5) )\\\\2 \ log_5 \ x = log_5 \ 5+ log_5 (x - (6)/(5) )\\\\2 \ log_5 \ x = log_5 \ ( 5(x - (6)/(5) ))\\\\x^2 = 5(x - (6)/(5))\\\\x^2 = 5x - 6\\\\x^2 - 5x + 6 = 0\\\\x^2 - 2x - 3x + 6 = 0\\\\x(x - 2 ) - 3 (x - 2) = 0\\\\(x - 3)(x-2) = 0\\\\x = 3 , x = 2

User ZZzzZZzz
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