Question

Cho tam giác ABC vuông tại A, cạnh AB =6, BC = 10, kẻ đường cao AH vuông góc với ÁC (H thuộc AC). Tính độ dài cạnh AC

Answer 1

AC = 8

Explanation:

Xét tam giác ABC vuông tại A:

`AB^2 + AC^2 = BC^2 (Pytago)\\=> AC = √(BC^2 - AB^2)\\=> AC = √(10^2 - 6^2)\\=> AC = √(100-36)\\=>AC = √(64)\\=> AC = 8`

Answer 2

Length of side AC = 8 centimeter (Approx.)

Explanation:

In given right triangle

Length of side AB = 6 centimeter

Length of side BC = 10 centimeter

Find:

Length of side AC

Computation:

Length of side AB (Base) = 6 centimeter

Length of side BC (Hypotenuse) = 10 centimeter

Length of side AC (Perpendicular)

Perpendicular = √Hypotenuse² - Base²

Length of side AC = √Length of side BC² - Length of side AB²

Length of side AC = √10² - 6²

Length of side AC = √100 - 36

Length of side AC = √64

Length of side AC = 8 centimeter (Approx.)