Question

The length of a rectangle should be 8 meters longer than 7 times the width. If the length must be

between 43 and 106 meters long, what are the restrictions for the width, x?

Answer 1

The restrictions for x would be 14 > x > 5.

Explanation:

Let the length of the rectangle be y and the width be x.

That being said, the equation would be as follows:

`y = 7x + 8`

`y - 8 = 7x`

`x = (y-8)/(7)`

Therefore, substituting the two values of y into the equations, we would get:

`x = (43-8)/(7)`

`x = (35)/(7)`

`x = 5`

And:

`x = (106-8)/(7)`

`x = (98)/(7)`

`x = 14`

Therefore, x would be between 5 and 14, and the restrictions for x would be 14 > x > 5.

Hope this helped!