Question

Someone please help T.T I need help ASAP

Answer 1

Explanation:

Given that,

The quadratic equation that models the ball's height above the ground h, t seconds after it was thrown is given by :

`h=-16t^2+108t+28` ...(1)

(a) For maximum height, put dh/dt = 0

So,

`(d(h))/(dt)=(d)/(dt)(-16t^2+108t+28)=0\\\\-32t+108=0\\\\t=(108)/(32)=3.37\ s`

Put the value of t in equation (1).

So,

`h=-16(3.37)^2+108(3.37)+28\\\\h=210.24\ ft`

(b) When the ball reaches the ground,

h = 0

So,

`-16t^2+108t+28=0\\\\t=7\ s`

So, the ball hits the ground in 7 seconds.