Question

Read the following reactions. Reaction 1: CaO(s) + CO2(g) → CaCO3(s) Reaction 2: H2O(g) → H2O(l) Which reaction leads to an increase in entropy? Only Reaction 1 Only Reaction 2 Both Reaction 1 and 2 Neither Reaction 1 nor 2

Answer 1

Answer: Neither Reaction 1 nor 2

Step-by-step explanation:

Answer 2

Answer: In the given reactions neither reaction 1 nor 2 reaction leads to an increase in entropy.

Step-by-step explanation:

The degree of randomness present in the molecules of a substance is called entropy.

In gases, molecules are held by weak forces due to which they move apart from each other. Hence, they have high entropy.

In liquids, molecules are a little close to each other so they have less entropy than gases.

In solids, molecules are tightly held together so they have least or negligible entropy.

As reaction 1 is
`CaO(s) + CO_(2)(g) \rightarrow CaCO_(3)(s)` and it shows that product is in solid state. Therefore, entropy is decreasing.

As reaction 2 is
`H_(2)O(g) \rightarrow H_(2)O(l)` and it shows that gas is converted into liquid. Therefore, entropy is also decreasing here.

Thus, we can conclude that in the given reactions neither reaction 1 nor 2 reaction leads to an increase in entropy.