Cuanto me da como resultado

asked Mar 13, 2022 13.7k views

3 votes

7.9k points

Please log in or register to add a comment.

4 votes

Explanation:

1)
$(-4)^2{\cdot}(-4)$

We know that,
$a^x{\cdot}a^y=a^(x+y)$

$(-4)^2{\cdot}(-4)=(-4)^(2+1)\\\\=(-4)^3\\\\=64$

2)
$(-2)^5{\cdot} (-2)^3$

Again using above property,

$(-2)^5{\cdot} (-2)^3=(-2)^8\\\\=256$

3)
5^(-3)

We know that,

a^(-x)=(1)/(a^x)

So,

$5^(-3)=(1)/(5^3)\\\\=(1)/(125)$

4)
$2.5^2=2.5* 2.5\\\\=6.25$

Hence, this is the required solution.