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Consider a 92.0 kg ice skater who is spinning on the ice. What is the moment of inertia of the skater, if the skater is approximated to be a solid cylinder that has a 0.140 m radius and is rotating about the center axis of the cylinder.

1 Answer

3 votes

Answer:


I=0.902kg*m^2

Step-by-step explanation:

From the question we are told that:

Mass
m=92.0kg

Radius
r=0.140m

Generally the equation for moment of Inertia is mathematically given by


I = 0.5*m*r^2


I=0.5*(92)*0.14^2


I=0.902kg*m^2

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