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A 12 kg hanging sculpture is suspended by a 80-cm-long, 6.0 g steel wire. When the wind blows hard, the wire hums at its fundamental frequency. What is the frequency of the hum

1 Answer

5 votes

Answer:


F=78.3hz

Step-by-step explanation:

From the question we are told that:

Mass
m=12

Length
l=80cm=0.8m

Linear density
\mu= 6.0g

Generally the equation for Frequency is mathematically given by


F=(1)/(2l)\sqrt{(T)/(K)}


F=(1)/(2(0.8))\sqrt{(12*9.8*0.8)/(6*10^(-3))}


F=78.3hz

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