Question

g is incident on 3 successive sheets of polarizing material. The transmission axis of the first sheet is vertical. The transmission axis of the second sheet is at 30 degrees from vertical. The transmission axis of the third is horizontal. What is the intensity of the light emerging from the third sheet

Answer 1

The intensity of light passing from the third polarizer is 3Io/16.

Step-by-step explanation:

The law of Malus is given by

`I=I_o cos^2\theta`

Let the incident intensity of light is Io.

The intensity of light passing from the first polarizer is

`I' = (I_o)/(2)`

The intensity of light passing from the second polarizer is

`I''=(I_o)/(2)* cos^230 =(3I_o)/(8)`

The intensity of light passing from the third polarizer is

`I''' = (3I_o)/(8)* cos^2 60\\\\\\I''' = (3I_o)/(16)`