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If the satellite weighs 1000g, orbits the Earth at an energy of 9.8 × 10 ^ 9j, what is the speed of the satellite?

1 Answer

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Answer:

1.4×10⁵ m/s

Step-by-step explanation:

Applying,

K = mv²/2............. Equation 1

Where K = Energy of the satellite, m = mass of the satellite, v = speed of the satellite.

make v the subject of the equation

v = √(2K/m)............ Equation 2

From the question,

Given: K = 9.8×10⁹ J, m = 1000 g = 1 kg

Substitute these values into equation 2

v = √(2×9.8×10⁹/1)

v = √(1.96×10¹⁰)

v = 1.4×10⁵ m/s

User Paul Tobias
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