Question

A uniformly charged disk of radius 35.0 cm carries charge with a density of 7.9 x 10-3 C/m2. Determine the magnitude of the electric field on the axis of the disk at 50.0 cm from the center of the disk. Record the answer to the nearest tenth of a MN/C (mega N/C).

Answer 1

E= 80.71 MegaN/C

Step-by-step explanation:

The radius of the disk is 35.0 cm.

The charge density is 7.9 x 10^-3 C/m^2

The distance from the center of the disk is 50.0 cm

The electric field is given by the expression as shown below:

`E=2 \pi k_(e) \sigma\left[1-(x)/(\left(R^(2)+x^(2)\right)^(1 / 2))\right]`

Plugging the values in the above expression,

E = (2 *3.14 * 7.9 *10^-3 * 9 *10^9) *(1-(0.5/(sqrt(0.5^2+ 0.35^2)))

E= 80.71 MegaN/C