Question

The density of dry air at room temperature and atmospheric pressure Is 1.2 kg m-3. What volume would 6 kg of dry air occupy under these conditions?​

Answer 1

V = 5 m³

Step-by-step explanation:

The density of air, d = 1.2 kg/m³

Mass of the dry air, m = 6 kg

We need to find the volume o the gas. We know that, the density of an object is given by mass divided by its volume. So,

`d=(m)/(V)\\\\V=(m)/(d)\\\\V=(6)/(1.2)\\\\V=5\ m^3`

So, the volume of the dry air is 5 m³.