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Two basketballs are thrown along different paths. Determine if the basketballs’ paths are parallel to each

other, perpendicular or neither. Explain your reasoning.

o The first basketball is along the path 3x + 4y = 12
o The second basketball is along the path -6x – 8y = 24

User Da Coconut
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1 Answer

4 votes

Answer:

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

Explanation:

Remember that:

  • Two lines are parallel if their slopes are equivalent.
  • Two lines are perpendicular if their slopes are negative reciprocals of each other.
  • And two lines are neither if neither of the two cases above apply.

So, let's find the slope of each equation.

The first basketball is modeled by:


\displaystyle 3x+4y=12

We can convert this into slope-intercept form. Subtract 3x from both sides:


4y=-3x+12

And divide both sides by four:


\displaystyle y=-(3)/(4)x+3

So, the slope of the first basketball is -3/4.

The second basketball is modeled by:


-6x-8y=24

Again, let's convert this into slope-intercept form. Add 6x to both sides:


-8y=6x+24

And divide both sides by negative eight:


\displaystyle y=-(3)/(4)x-3

So, the slope of the second basketball is also -3/4.

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

User Shafiqul
by
8.3k points

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