Answer:
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
Explanation:
Remember that:
- Two lines are parallel if their slopes are equivalent.
- Two lines are perpendicular if their slopes are negative reciprocals of each other.
- And two lines are neither if neither of the two cases above apply.
So, let's find the slope of each equation.
The first basketball is modeled by:
![\displaystyle 3x+4y=12](https://img.qammunity.org/2022/formulas/mathematics/high-school/fgfz3yhwwtzpd8osbhp86e81ptmzfllppx.png)
We can convert this into slope-intercept form. Subtract 3x from both sides:
![4y=-3x+12](https://img.qammunity.org/2022/formulas/mathematics/high-school/xf7m7d5xfwxq33te9fyvwyi8aop1x5thh4.png)
And divide both sides by four:
![\displaystyle y=-(3)/(4)x+3](https://img.qammunity.org/2022/formulas/mathematics/high-school/512q10xjhkrgcxe5hqg0uhrdehlivrercs.png)
So, the slope of the first basketball is -3/4.
The second basketball is modeled by:
![-6x-8y=24](https://img.qammunity.org/2022/formulas/mathematics/high-school/yev8vffx4i8mif74j3zt12scezwtdjtxxt.png)
Again, let's convert this into slope-intercept form. Add 6x to both sides:
![-8y=6x+24](https://img.qammunity.org/2022/formulas/mathematics/high-school/f4g0eozgok4y57tmjawibkq0u6aw8hsisa.png)
And divide both sides by negative eight:
![\displaystyle y=-(3)/(4)x-3](https://img.qammunity.org/2022/formulas/mathematics/high-school/ig6hr2u7xj1g1ajwwfjwgljqcmqsi6cztc.png)
So, the slope of the second basketball is also -3/4.
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.