Answer:
see below
Explanation:
Part A: (72)^x = 1
Take the log base 72 of each side
log72(72^x) = log 72(1)
We know log a^b = b log a
x log72(72) = log72(1)
x = log72(1)
x = 0
Part A: (70)^x = 1
Take the log base 70 of each side
log70(70^x) = log70(1)
We know log a^b = b log a
x log70(70) = log70(1)
x = log70(1)
x = 0