Answer:
The shorter leg is five feet, the longer leg is 12 feet, and the hypotenuse is 13 feet.
Explanation:
Let the shorter leg be x.
Since the longer leg is seven feet longer than the shorter leg, the length of the longer leg can be modeled by (x + 7).
Since the triangle is a right triangle, we can use the Pythagorean Theorem, given by:
![a^2+b^2=c^2](https://img.qammunity.org/2022/formulas/mathematics/college/a7evvahf9asnkyok9myxuf24e8ciywglc7.png)
Where a and b are the side lengths and c is the hypotenuse.
The hypotenuse is 13 and the legs are x and (x + 7). Substitute:
![(x)^2+(x+7)^2=(13)^2](https://img.qammunity.org/2022/formulas/mathematics/college/uukipqdl4rcuf1zfu2lhabok3hn7ee46fw.png)
Square:
![x^2+x^2+14x+49=169](https://img.qammunity.org/2022/formulas/mathematics/college/nzok7d43n9vzaauue5475q6li91zuydyjs.png)
Simplify:
![2x^2+14x-120=0](https://img.qammunity.org/2022/formulas/mathematics/high-school/gkng6144xvn84327sak3hacqenvifuhsyl.png)
We can divide both sides by two:
![x^2+7x-60=0](https://img.qammunity.org/2022/formulas/mathematics/college/n7eo1goj1vkritau99s1e7n3az6t7tat2i.png)
Factor:
![(x-5)(x+12)=0](https://img.qammunity.org/2022/formulas/mathematics/college/xt2ulo3m7vlirq93j0sk11swc8k7pixufo.png)
Zero Product Property:
![x-5=0\text{ or }x+12=0](https://img.qammunity.org/2022/formulas/mathematics/college/2vod427k87hho5m561qddlos64m0zj96sz.png)
Solve for each case:
![x=5\text{ or } x=-12](https://img.qammunity.org/2022/formulas/mathematics/college/eo1nji8zw8lefhgv6n2xvzoh5c3qbouzf2.png)
Since lengths cannot be negative, we can ignore the negative answer. So, our only solution is:
![x=5](https://img.qammunity.org/2022/formulas/mathematics/high-school/vndazmbyqu3wu39zuuyki1lbj4enalp9m1.png)
The shorter leg is five feet, the longer leg will be (5 + 7) or 12 feet. And the hypotenuse is 13 feet as given.