Given:
Two box plots for Brand A and Brand B.
To find:
The correct statement for the given box plots.
Solution:
In a box plot, the left end of the box represents the first quartile
, right end of the box represents the third quartile
and the line inside the box represents the median.
The interquartile range of a data set is:
![IQR=Q_3-Q_1](https://img.qammunity.org/2022/formulas/mathematics/high-school/9rgm6o84pprpwvy1ai39dbg06zwbkwak8q.png)
From the box plot of Brand A, it is clear that
![Q_1=70](https://img.qammunity.org/2022/formulas/mathematics/high-school/yvfgo66g26xso3amvvs01m0xav8wkj444h.png)
![Median=75](https://img.qammunity.org/2022/formulas/mathematics/high-school/ldm0xquj6jb5vkfkm3tx6ej20ymdnh2jel.png)
![Q_3=80](https://img.qammunity.org/2022/formulas/mathematics/high-school/9nqota47819vuc3vaj37u87g3trppawn1t.png)
So, the interquartile range (IQR) for brand A is:
![IQR=80-70](https://img.qammunity.org/2022/formulas/mathematics/high-school/qovkhqhmheh615jkck0394g6f9cy7d8y1b.png)
![IQR=10](https://img.qammunity.org/2022/formulas/mathematics/high-school/z6ldf3c9dja9c3krrnhllwxzobocor2jaa.png)
From the box plot of Brand B, it is clear that
![Q_1=50](https://img.qammunity.org/2022/formulas/mathematics/high-school/c9rnpyozzsr5pp86r9ok6856wi02mdy47p.png)
![Median=60](https://img.qammunity.org/2022/formulas/mathematics/high-school/84jyv213smoncbnnwgwsm9xon96m6k78za.png)
![Q_3=70](https://img.qammunity.org/2022/formulas/mathematics/high-school/w6l9kipmsiv2k4wrjwtdy3h1e5t6y7denn.png)
So, the interquartile range (IQR) for brand B is:
![IQR=70-50](https://img.qammunity.org/2022/formulas/mathematics/high-school/7oukf1l0dlnqi3r9uwghzgh656p27vr77f.png)
![IQR=20](https://img.qammunity.org/2022/formulas/mathematics/high-school/4zuhdy4qoo27i457197cg4xa93qen4bksz.png)
The median for brand A, $75, is greater than the median for brand B, $60.
The interquartile range (IQR) for brand A, $10, is less than the IQR
brand B. $20.
Therefore, the correct options are B and C.