Question

A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at rest. The final speed of the child at the bottom is 6.81 m/s. Find the average force of friction between the child and the slide.

Answer 1

`F=32.24N`

Explanation:

From the question we are told that:

Height
`h= 2.75 m`

Length
`l = 5.25 m`

Mass
`m=45kg`

Final speed
`v_f=6.81`

Generally the equation for Potential Energy P.E is mathematically given by

`P.E=mgh`

Therefore

Initial potential energy

`P.E_1=45*9.8*2.75 \\\\P.E_1= 1212.75 J`

Generally the equation for Kinetic Energy K.E is mathematically given by

`K.E=0.5mv^2`

Therefore

Final kinetic energy

`K.E_2= 1/2*45*6.81*6.81 \\\\K.E_2= 1043.46J`

Generally the equation for Work_done is mathematically given by

`W=P.E_1-K.E_2\\\\W=169.3`

Therefore

`F=(W)/(d)\\\\F=(169.3)/(5.25)`

`F=32.24N`