Question

Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very few collisions with other molecules. Express your answer using two significant figures.

Answer 1

The right solution is "24.39 per sec".

Step-by-step explanation:

According to the question,

⇒
`v=(502.1)/(√(3) )`

`=289.9 \ m/s`

The time will be:

⇒
`t=(d)/(v)`

`=(2* 6)/(289.9)`

`=(12)/(289.9)`

`=0.041 \ sec`

hence,

⇒
`N=(1)/(t)`

`=(1)/(0.041)`

`=24.39 \ per \ sec`