Question

Vincent dissolves 6.5 g of bromic acid, HBrO3, to prepare 600.0 mL of solution. Calculate the concentration of the acid Vincent produced.

Answer 1

Answer: The concentration of the acid Vincent produced is 0.083 M.

Step-by-step explanation:

Given: Mass = 6.5 g

Volume = 600.0 mL (1 mL = 0.001 L) = 0.6 L

Moles is the mass of substance divided by its molar mass. So, moles of bromic acid (molar mass = 128.91 g/mol) are calculated as follows.

`Moles = (mass)/(molar mass)\\= (6.5 g)/(128.91 g/mol)\\= 0.05 mol`

Molarity is the number of moles of a substance present in liter of a solution.

Therefore, molarity (concentration) of the given solution is calculated as follows.

`Molarity = (no. of moles)/(Volume (in L))\\= (0.05 mol)/(0.6 L)\\= 0.083 M`

Thus, we can conclude that the concentration of the acid Vincent produced is 0.083 M.