Question

A point source of light illuminates an aperture 1.70 m away. A 11.0 cm -wide bright patch of light appears on a screen 0.800 m behind the aperture. Part A How wide is the aperture

Answer 1

7.48 cm

Step-by-step explanation:

The diagrammatic representation of information is shown in the image below:

From the image, Δ X₁X₂ and Δ Y₁Y₂ are equivalent triangles.

where;

X₁X₂ = width of the aperture

Using equivalent triangles, It implies that:

`\implies (X_1X_2)/(Y_1Y_2) = (1.70)/(1.70+0.800) \\ \\ \implies X_1X_2=(1.70)/(1.70+0.800)* 11.0`

`X_1X_2= (1.70)/(2.50)* 11.0 cm`

X₁X₂ = 7.48 cm