Answer:
So, both the functions are neither even and nor odd.
Explanation:
A function is even if g(x) = g(-x) and odd if g(x) = - g(x).
g(x) = |x-3|
g (-x ) = | -x -3 |
So, the function is neither even and nor odd.
g (x) = x + x²
g (- x) = (- x) + (- x) ² = - x + x²
So, the function is neither even and nor odd.