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what is the left hand limit of g(x)=

\frac{ {x}^(2) - 25 }{x - 5}
as x aproaches 5​

User Turun
by
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1 Answer

2 votes

10

Explanation:


\displaystyle \lim_(x \to 5) \left((x^2 - 5)/(x - 5) \right)= \lim_(x \to 5) ((x+5)(x-5))/((x-5))

or


\displaystyle \lim_(x \to 5) (x + 5) = 10

User Marlos Carmo
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