Question

Write a program that reads in an integer and displays a diamond pattern as described below. the integer determines the the number of plus characters in the widest (center) part of the diamond. the program should use nested loops. you can assume the number read in is odd.

Here is one sample run:


Diamond Width: 7

+

+++

+++++

+++++++

+++++

+++

+

Answer 1

The student needs to write a program that outputs a diamond pattern using an odd integer to define the width of the diamond's center. A sample Python program is provided, using nested loops to construct the pattern with spaces and plus symbols.

Step-by-step explanation:

The student is asking for a program to generate a diamond pattern of plus symbols, where the width of the diamond's largest section is defined by an input integer. The description indicates that the integer will be odd, which is a typical characteristic to ensure a symmetrical pattern. Nested loops will be used to generate the spaces and plus symbols for each row of the diamond.

Sample Python Program

Here's how you could write a simple program in Python to achieve this:

width = int(input("Diamond Width: "))
n = width // 2
for i in range(n):
print(" " * (n - i) + "+" * (2 * i + 1))
for i in range(n, -1, -1):
print(" " * (n - i) + "+" * (2 * i + 1))

This program uses two for loops: the first to print the top half of the diamond and the second to print the bottom half. Spaces are added to align the plus symbols to form the diamond shape.

Answer 2

The program in Python is as follows:

numrows = int(input())

n = 0

for i in range(1, numrows + 1):

for j in range (1, (numrows - i) + 1):

print(end = " ")

while n != (2 * i - 1):

print("*", end = "")

n = n + 1

n = 0

print()

k = 1; n = 1

for i in range(1, numrows):

for j in range (1, k + 1):

print(end = " ")

k = k + 1

while n <= (2 * (numrows - i) - 1):

print("*", end = "")

n = n + 1

n = 1

print()

Step-by-step explanation:

This gets the number of rows

numrows = int(input())

This initializes the upper part of the diamonds

n = 0

The following iteration prints the spaces in each row

for i in range(1, numrows + 1):

for j in range (1, (numrows - i) + 1):

print(end = " ")

The following iteration prints * in the upper part of the diamond

while n != (2 * i - 1):

print("*", end = "")

n = n + 1

n = 0

This prints a new line

print()

The lower part of the diamond begins here

k = 1; n = 1

The following iterations print the spaces in each row

for i in range(1, numrows):

for j in range (1, k + 1):

print(end = " ")

k = k + 1

The following iteration prints * in the lower part of the diamond

while n <= (2 * (numrows - i) - 1):

print("*", end = "")

n = n + 1

n = 1

This prints a new line

print()