Question

i'm a period of 2 1/4 hours, 5 1/2 gallons of water leaker from a water tank. how much water did the tank lose per hour?

Answer 1

C. 11/2÷9/4

Explanation:

This question can be solved using a rule of three.

In 2 + \frac{1}{4} = \frac{2*4 + 1}{4} = \frac{9}{4}2+

4

1

=

4

2∗4+1

=

4

9

hours, the tank loses 5 + \frac{1}[2} = \frac{5*2 + 1}{2} = \frac{11}{2} gallons. How much does it lose in an hour?

1 hour - x gallons

9/4 hours - 11/2 gallons

So

\frac{9x}{4} = \frac{11}{2}

4

9x

=

2

11

x = \frac{\frac{11}{2}}{\frac{9}{4}}x=

4

9

2

11

So the correct answer is C.