Question

How many moles are in 275g
(Ca(NO3)2

Answer 1

1.68 mol Ca(NO₃)₂

Step-by-step explanation:

Answer 2

1.68 mol Ca(NO₃)₂

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Table
• Moles
• Compounds

Stoichiometry

• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 275 g Ca(NO₃)₂

[Solve] mol Ca(NO₃)₂

Step 2: Identify Conversions

[PT] Molar Mass of Ca: 40.08 g/mol

[PT] Molar Mass of N: 14.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of Ca(NO₃)₂: 40.08 + 2[14.01 + 3(16.00)] = 164.10 g/mol

Step 3: Convert

1. [DA] Set up:
   `\displaystyle 275 \ g \ Ca(NO_3)_2((1 \ mol \ Ca(NO_3)_2)/(164.10 \ g \ Ca(NO_3)_2))`
2. [DA] Divide [Cancel out units]:
   `\displaystyle 1.67581 \ mol \ Ca(NO_3)_2`

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.67581 mol Ca(NO₃)₂ ≈ 1.68 mol Ca(NO₃)₂