Question

Over ten years, the population of fish in a lake increases by 3%. After the increase, there are 10,094 fish. Which expressions are equivalent to the number of fish ten years before? Select all that apply.

Answer 1

9800 Fish

Explanation:

Answer 2

9800 Fish

Explanation:

According to The question,

• Given, the population of fish in a lake increases by 3% for over ten years, after the increase there are 10094 fish .

The number of fish ten years before is
`10094 * (100)/(103)` ⇔ 9800 fish