Question

NEED QUICKLY
Write the equation of the line shown below?

Answer 1

y = x + 2

Explanation:

General formula for any straight line:

y = mx + c

Where

m = gradient

c = constant

m = y2 - y1/x2 - x1

m = (4 - ( -2))/(2 - ( -4))

m = 6/6

m = 1

y = (1)x + c

y = x + c

Substitute any coordinate from the line of the equation.

4 = 2 + c

c = 2

substitute m and c into general formula

y = mx + c

y = x + 2

Answer 2

Equation is : y = x + 2

Explanation:

To find the equation of the we need two points through which the line passes.

Let it be (2 , 4) and ( -4 , - 2)

The standard equation of line is : y = mx + b , where m is the slope, b is the

y-intercept.

Step 1 : Find the slope, m

`slope , m = (y_2 - y_1)/(x_2 - x_1)`
`[ \ where \ (x_1, y _ 1 ) = ( 2 , 4 ) \ , \ (x_2 , y_ 2 ) = ( -4, -2 ) \ ]`

`m = (-2-4)/(-4-2)\\\\ = (-6)/(-6)\\\\ = 1`

Step 2 : Find the equation of the line.

`( y - y_1) = m(x- x_1)\\\\(y - 4) = 1 ( x - 2)\\\\y - 4 = x - 2 \\\\y = x - 2 + 4 \\\\y = x + 2`