Question

Please help! urgently

Answer 1

sinC =
`(4√(41) )/(41)`

Explanation:

We require to find the side DE before finding sinC

Using Pythagoras' identity in the right triangle

DE² + CE² = CD²

DE² + 5² = (
`√(41)` )²

DE² + 25 = 41 ( subtract 25 from both sides )

DE² = 16 ( take the square root of both sides )

DE =
`√(16)` = 4 , then

sinC =
`(opposite)/(hypotenuse)` =
`(DE)/(CD)` =
`(4)/(√(41) )` , rationalise the denominator

sinC =
`(4)/(√(41) )` ×
`(√(41) )/(√(41) )` =
`(4√(41) )/(41)`