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A solenoid used to produce magnetic fields for research purposes is 2.5 mm long, with an inner radius of 30 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.4 TT in the center. Part A Given this, how large a current does it carry

User Dotnix
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1 Answer

10 votes

Answer:

2.14 A

Step-by-step explanation:

L = 2.5 mm, N = 1300, B = 1.4 T, find I

B = μ₀N*I/L

so I = B*L/(μ₀N) = 1.4 * 0.0025/(4π x 10⁻⁷ x 1300) = 2.14 A

User Jamal Zare
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