Answer:
The amount saved in a year is $ 278.6.
Step-by-step explanation:
current, I = 0.275 A
Voltage, V = 120 V
cost = $ 0.20 per kWh
The energy spent in 1 year is given by
E = V I t
E = 120 x 0.275 x 365 x 24 x 3600
E = 1.04 x 10^9 J
1 kWh = 3.6 x 10^6 J
So,
E = 288.9 kWh
So, the cost is
C = $ 0.2 x 288.9 = $ 57.78
So, the amount saved = $ 336.384 - $ 57.78 = $ 278.6