Question

A football is projected at an angle of 30 from the ground with a n initial velocity of 10 m/s, take acceleration due to gravity is g= 10m/s2 .what is the time of flight

Answer 1

Answer: i dont know

Step-by-step explanation:

Answer 2

`{ \bf \: time \: of \: flight : s = 0} \\ { \tt \: s \: is \: displacement} \\ \\ s = ut + (1)/(2) a {t}^(2) \\ 0 = u \sin( \theta) t - (1)/(2) g {t}^(2) \\ u \sin( \theta)t = (1)/(2) g {t}^(2) \\2 u \sin( \theta) = gt \\ { \boxed{ \tt{formular : time \: of \: flight = (2u \sin( \theta) )/(g) }}} \\ t = (2 * 10 * \sin(30 \degree) )/(10) \\ { \green{ \boxed{ \tt{ \bf{answer : { \tt{time \: of \: flight =1 \: second }}}}}}} \\ \\ { \tt{becker \: jnr}}`