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Given The following right triangle, what is the ratio of Cos(b) A) 5/13 B) 5/12 C) 13/5 D) 12/13
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Given The following right triangle, what is the ratio of Cos(b)

A) 5/13
B) 5/12
C) 13/5
D) 12/13

Given The following right triangle, what is the ratio of Cos(b) A) 5/13 B) 5/12 C-example-1
User Perimasu
by
8.9k points

1 Answer

2 votes

Answer:

A. 5/13

Explanation:

Cos = Adjacent/Hypotenuse

Adjacent of B = 5

Hypotenuse = 13

Hence CosB = 5/13

User Rich Homolka
by
7.9k points
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