Question

In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm.
Find the area of triangle ABC.

Answer 1

Area = 42.43 square cm

Explanation:

Using Heron's Formula :

`Area = √(s* (s-a) * (s-b) *(s -c)) \ , \ where \ s \ =\ (a+ b+ c)/(2)`

Find Area :

`s = (11 + 9 + 10 )/(2) = (30)/(2) = 15`

`Area = \sqrt{15 * ( 15 - 11 ) * { (15 - 9 ) * ( 15 -10)}\\\\`

`= √(15 * 4 * 6 * 5)\\\\=√(1800)`

`= 42 . 43 \ cm^2`