Question

What would be the mass of 44.8 L of CO2 gas at STP?
show work if possible

Answer 1

`m=88.02g`

Step-by-step explanation:

Hello there!

In this case, for this ideal gas law problem, it turns out necessary for us to remember that one mole of any gas is contained in 22.4 L at STP and therefore, we can use the following ratio to calculate the moles in 44.8 L of CO2:

`(1mol)/(22.4L) =(x)/(44.8L)\\\\x= (1mol*44.8L)/(22.4L)=2mol`

Finally, since the molar mass of CO2 is 44.01 g/mol, we calculate the mass as follows:

`m=2mol*(44.01g)/(1mol)\\\\m=88.02g`

Regards!