Question

A constant voltage of 11.00 V has been observed over a certain time interval across a 1.20 H inductor. The current through the inductor, measured as 1.00 A at the beginning of the time interval, was observed to increase at a constant rate to a value of 7.00 A at the end of the time interval. How long was this time interval

Answer 1

0.65 sec

Step-by-step explanation:

V = L*ΔI/Δt

so Δt = L*ΔI/V = 1.20 * (7.00 - 1.00)/11.00 = 0.65 sec