Question

HELP ASAP!!! if 600.0 grams HF reacts with excess SiO2, how many grams of H2O are produced? Use the following molar masses: HF= 20.01g

H2O=18.02g
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Answer 1

Answer: The mass of water produced is 180.02 g

Step-by-step explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` ......(1)

Given mass of HF = 600.0 g

Molar mass of HF = 20.01 g/mol

Plugging values in equation 1:

`\text{Moles of HF}=(600.0g)/(20.01g/mol)=29.98 mol`

The given chemical equation follows:

`SiO_2+6HF\rightarrow H_2SiF_6+2H_2O`

By the stoichiometry of the reaction:

If 6 moles of HF produces 2 moles of water

So, 29.98 moles of HF will produce =
`(2)/(6)* 29.98=9.99mol` of water

Molar mass of water = 18.02 g/mol

Plugging values in equation 1:

`\text{Mass of water}=(9.99mol* 18.02g/mol)=180.02g`

Hence, the mass of water produced is 180.02 g