Answer:
162.4g of CO2 are produced
Step-by-step explanation:
The combustion of ethanol, C2H5OH, occurs as follows:
2C2H5OH + 7O2 → 4CO2 + 6H2O
Where 2 moles of C2H5OH produce 4 moles of CO2.
To solve this question we need to convert the mass of ethanol to moles. Then, the moles of ethanol to moles of CO2 using the balanced reaction and to mass:
Moles C2H5OH -Molar mass: 46.07g/mol-
85.0g * (1mol / 46.07g) = 1.845 moles C2H5OH
Moles CO2:
1.845 moles C2H5OH * (4mol CO2 / 2mol C2H5OH) = 3.69 moles CO2
Mass CO2-Molar mass: 44.01g/mol-:
3.69 moles CO2 * (44.01g/mol) =
162.4g of CO2 are produced