Question

A 47 kg mass is moving across a horizontal surface at 8 m/s. What is the force required to bring the mass to a stop in 4.1 seconds? (Hint: This is a multi-step calculation and your answer should come out to be negative). Write your answer to one decimal place.

Answer 1

Force = -91.7 Newton

Step-by-step explanation:

Given the following data;

Mass = 47 kg

Time = 4.1 seconds

Initial velocity = 8 m/s

Since the object comes to a stop, its final velocity would be equal to zero.

To find the force required to bring it to stop;

First of all, we would determine the acceleration of the object;

Mathematically, acceleration is given by the equation;

`Acceleration (a) = (final \; velocity - initial \; velocity)/(time)`

Substituting into the equation;

`a = (0 - 8)/(4.1)`

`a = (-8)/(4.1)`

Acceleration, a = -1.95 m/s²

Next, we would determine the force required to bring the object to stop;

`Force = mass * acceleration`

`Force = 47 * -1.95`

Force = -91.65 ≈ 91.7 Newton