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0=(x-8) (3x-5) show all work

User Vladko
by
4.4k points

1 Answer

3 votes

Answer:

x = 8


x=1(2)/(3)

Explanation:

0 = (x - 8)(3x - 5)

(x - 8)(3x - 5) = 0

x(3x - 5) - 8(3x - 5) = 0

3x² - 5x - 8(3x - 5) = 0

3x² - 5x - 24x + 40 = 0

3x² - 29x + 40 = 0


x=\frac{-b±\sqrt{b^(2)-4ac } }{2a}

Ignore the A before the ±. It wouldn't let me type it correctly.

3x² - 29x + 40 = 0

a = 3

b = - 29

c = 40


x=\frac{-(-29)±\sqrt{(-29)^(2)-4((3)(40)) } }{2(3)}


x=(-(-29)±√(841-4((3)(40)) ) )/(2(3))


x=(29±√(841-480) )/(2(3))


x=(29±√(361) )/(2(3))


x=(29±19 )/(2(3))


x=(29±19 )/(6)

Two separate equations


x=(29+19 )/(6)


x=(48 )/(6)

x = 8


x=(29-19 )/(6)


x=(10 )/(6)


x=(5 )/(3)


x=1(2)/(3)

User EzekielDFM
by
4.8k points