Question

After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 55.0 cm . She finds that the pendulum makes 100 complete swings in a time of 130 s . What is the value of g on this planet?

Answer 1

Step-by-step explanation:

Given:

l = 55.0 cm = 0.550 m

T = (130 s)/100 = 1.30 s

g = ?

The period of a pendulum is given by

`T=2 \pi \sqrt{ (l)/(g)}`

Solving for T, we get

`(T^2)/(4 \pi^2)=(l)/(g)`

Solving for g, we get

`g=(4 \pi^2l)/(T^2)=(4 \pi^2(0.550 m))/((1.30\:s)^2)=12.8\:(m)/(s^2)`