Question

What are the solutions to the quadratic equation below?
4x^2 + 28x + 49 = 5

Answer 1

C.

`x=(-7±√(5 ) )/(2)`

Explanation:

4x² + 28x + 49 = 5

4x² + 28x + 49 - 5 = 0

4x² + 28x + 44 = 0

4(x² + 7x + 11) = 0

4(x² + 7x + 11) ÷ 4 = 0 ÷ 4

x² + 7x + 11 = 0

`x=\frac{-b±\sqrt{b^(2)-4ac } }{2a}`

Ignore the A before the ±. It wouldn't let me type it correctly.

a = 1

b = 7

c = 11

`x=\frac{-7±\sqrt{7^(2)-4((1)(11)) } }{2(1)}`

`x=(-7±√(49-4((1)(11)) ) )/(2(1))`

`x=(-7±√(49-44 ) )/(2(1))`

`x=(-7±√(5 ) )/(2(1))`

`x=(-7±√(5 ) )/(2)`

Answer 2

C

Explanation: