Question

How many different codes of 6 digits are possible if the first digit must be 3, 4, 5, or 6 and if the code may not end in 0? Hint: think of positions.

Answer 1

360000 possible codes

Explanation:

The first digit can only be one of four things and the last digit can't be zero.

4*10*10*10*10*9=360000