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Find the equation of the circle with center at (3, -2) and radius of 3.

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Answer:

(x -3)^2 +(y +2)^2 = 9

Explanation:

The standard form equation for a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

For your given center and radius, this is ...

(x -3)^2 +(y -(-2))^2 = 3^2

(x -3)^2 +(y +2)^2 = 9

User Leandro Ocampo
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