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What are the value of x in the equation x^2+4-1 =0
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What are the value of x in the equation x^2+4-1 =0

User David Wolever
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1 Answer

2 votes

Answer:

x = ±sqrt(3) i

Explanation:

x^2+4-1 =0

Combine like terms

x^2 +3 = 0

Subtract 3 from each side

x^2 +3-3 = 0-3

x^2 = -3

Take the square root of each side

sqrt(x^2) = sqrt(-3)

x = ±sqrt(3) sqrt(-1)

x = ±sqrt(3) i

User Sandra Schlichting
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