Answer:
Explanation:
(3,0),(4,1) ⇒ (x₁,y₁),(x₂,y₂)
to find the equation of the line
y-y₁= {(y₂-y₁)/(x₂-x₁)}(x-x₁)
y-0= [(1-0)/(4-3)] (x-3)
y-0 = 1/1(x-3)
y-0 = x-3
y= x-3+0
y=x-3
compare to y=mx+c, where m is the gradient and c is the intercept on y-axis
m=1, c=-3
∴the y-intercept of the line is -3