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Find the slope of the equation that goes through:
(-4,-14) and (-10,6)

1 Answer

6 votes

Hello.

In order to find the slope of the given line, we should use the slope formula:


\mathrm{\displaystyle(y2-y1)/(x2-x1)}

y₂= the y-coordinate of the second point (6

y₁= the y-coordinate of the first point (-14)

x₂=the x-coordinate of the second point (-10)

x₁=the x-coordinate of the first point (-4)

Let's plug in the values and solve:


\mathrm{\displaystyle(6-(-14))/(-10-(-4))=(6+14)/(-10+4) =(20)/(-6) =-(20)/(6) =-(10)/(3) }

Answer:


\Large\boxed{\sf{\displaystyle-(10)/(3) }}

I hope it helps.

Have a nice day.


\boxed{imperturbability}

User Kibowki
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