Question

The point-slope form of the equation of the line that passes through (-4, -3) and (12, 1) is y– 1 =1/4 (x – 12). What is the standard form of the equation for this line?

x - 4y = 8
x - 4y = 2
4x - y = 8
4x - y = 2 ​

Answer 1

x-4y = 8

Explanation:

y– 1 =1/4 (x – 12)

Multiply each side by 4

4y -4 = x-12

Subtract x from each side

-x +4y -4 = -12

Add 4 to each side

-x+4y -4+4 = -12 +4

-x+4y = -8

Multiply by -1

x-4y = 8